(1/16)x^2+(1/8)x-(15/16)=0

Solution for (1/16)x^2+(1/8)x-(15/16)=0 equation:

(1/16)x^2+(1/8)x-(15/16)=0


Domain of the equation: 16)x^2!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 8)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/16)x^2+(+1/8)x-(+15/16)=0

We multiply parentheses

x^2+(+1/16)x^2-(+15/16)=0

We get rid of parentheses

x^2+(+1/16)x^2-15/16=0

We calculate fractions


x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$